PhoneNumber
Write a function that accepts an array of 10 integers (between 0 and 9), that returns a string of those numbers in the form of a phone number.
Categories:
String.format()
First try, Prefixed numbers is fixed
we can simply cut out
public static String createPhoneNumber(int[] numbers) {
// Your code here!
String country = numbers[0] + "" + numbers[1] + "" + numbers[2];
String area = numbers[3] + "" + numbers[4] + "" + numbers[5];
String pop = "";
for (int i = 6; i <= numbers.length - 1; i++) {
pop = pop + numbers[i] + "";
} return "(" + country + ")" + " " + area + "-" + pop;
}
76ms
But There has an more elegant way to do so.
Use String.format()
public static String createPhoneNumber(int[] numbers){
return String.format("(%d%d%d) %d%d%d-%d%d%d%d",numbers[0],numbers[1],numbers[2],numbers[3],numbers[4],numbers[5],numbers[6],numbers[7],numbers[8],numbers[9] );
}
But this method have to compile formatter, which caused extra time.
Over all, we can use StringBuffer to put Strings together.
public static String createPhoneNumber(int[] numbers) {
// Your code here!
return new StringBuilder()
.append("(")
.append(numbers[0])
.append(numbers[1])
.append(numbers[2])
.append(") ")
.append(numbers[3])
.append(numbers[4])
.append(numbers[5])
.append("-")
.append(numbers[6])
.append(numbers[7])
.append(numbers[8])
.append(numbers[9])
.toString();
}
76ms
Actually, It did not saving time, but use less space.
So recommend third method.